-4.9x^2-214x+1.7=0

Solution for -4.9x^2-214x+1.7=0 equation:

-4.9x^2-214x+1.7=0

a = -4.9; b = -214; c = +1.7;
Δ = b2-4ac
Δ = -2142-4·(-4.9)·1.7
Δ = 45829.32
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-214)-\sqrt{45829.32}}{2*-4.9}=\frac{214-\sqrt{45829.32}}{-9.8}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-214)+\sqrt{45829.32}}{2*-4.9}=\frac{214+\sqrt{45829.32}}{-9.8}
$